The sum of the measures of the angles is 180. The sum of the measures of the second and third angles is two times the measure of the first angle. The third angle is 26 more than the second. Let x, y, and z represent the measures of the first, second, and third angles, respectively. Find the measures of the three angles.
Accepted Solution
A:
60,47,73Step-by-step explanation:Let the first angle be [tex]a[/tex] degreesLet the second angle be [tex]b[/tex] degreesLet the third angle be [tex]c[/tex] degreesIt is given that sum of angles is [tex]180[/tex] degrees.so,[tex]a+b+c=180[/tex] ...(i)It is given that sum of the measures of the second and third angles is two times the measure of the first angle.[tex]b+c=2\times a[/tex] ...(ii)It is given that the third angle is 26 more than the second.[tex]c=26+b[/tex] ...(iii)using (ii) and (iii),[tex]b+b+26=2a[/tex][tex]b+13=a[/tex]using (i),(ii) and (iii),[tex]a+b+c=a+a-13+26+b=a+a-13+26+a-13=3a[/tex][tex]3a=180[/tex][tex]a=60[/tex][tex]b=a-13=60-13=47[/tex][tex]c=26+b=26+47=73[/tex]