MATH SOLVE

4 months ago

Q:
# What is the axis of symmetry for f(x)=2x2+8x+8

Accepted Solution

A:

2x^2 + 8x + 8

= 2(x^2 + 4x) + 8

= 2 [ (x + 2)^2 - 4) + 8

axis of symmetry is x = -2 ( because of the (x + 2)^2 )

= 2(x^2 + 4x) + 8

= 2 [ (x + 2)^2 - 4) + 8

axis of symmetry is x = -2 ( because of the (x + 2)^2 )