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What is the axis of symmetry for f(x)=2x2+8x+8
5 months ago
Q:
What is the axis of symmetry for f(x)=2x2+8x+8
Accepted Solution
A:
2x^2 + 8x + 8
= 2(x^2 + 4x) + 8
= 2 [ (x + 2)^2 - 4) + 8
axis of symmetry is x = -2 ( because of the (x + 2)^2 )