For each of these lists of integers, provide a simple formula orrule that generates the terms of an integer sequence that beginswith the given list. Assuming that your formula or rule is correct,determine the next three terms of the sequence.a)3,6,11,18,27,38,51,66,83,102........b) 7, 11, 15, 19, 23, 27, 31, 35, 39, 43, ...c) 1, 10, 11, 100, 101, 110, 111, 1000, 1001, 1010, 1011,...d) 1, 2, 2, 2, 3, 3, 3, 3, 3, 5, 5, 5, 5, 5, 5, 5, ...f) 1, 3, 15, 105, 945, 10395, 135135, 2027025, 34459425,...g) 1, 0, 0, 1, 1, 1, 0, 0, 0, 0, 1, 1, 1, 1, 1, ...

Answer:The next three terms for each are: a) 123, 146, 171; b) 47,51,55; c) 10000,10001, 10010; d)8,8,8; f)654729075,13749310575,316234142225; g)0,0,0Step-by-step explanation:In a) the last number +(2i+1) in which i is the number of terms=1,2,3...b) n+4, for any last number, you add 4c) 1,0 and the same is repeated for the next decimald) n=sum of 2 previous different numbers. The frequency is given by 2i-1 in which is is the number of terms i=1,2,3...e) missingf) ni+1=n*(2i-1) in which ni+1 is the resulting number, n is the previous number and i is the number of terms=1,2,3...g) it is 1 for odd numbers and 0 for even numbers. The frequency is given by i+1, in which the number of terms i= 0,1,2,3...