i need help bruv. For the function y=x^2 - 5x - 6 . (a) Find the vertex(b) Find the y-intercept(c) Find the x-intercepts(Leave your answers in simplified radical form or, where appropriate, round to the nearest hundredth.)

Answer:a. Vertex = (2.5,-12.25)b. y-intercept = (0,-6)c. x-intercept = (6,0) ; (-1,0)Step-by-step explanation:a.Your equation is written as:[tex]y = ax^{2} + bx +c[/tex]The easiest way to find the vertex is writing the equation this way:[tex]y = a(x-h)^{2}+k[/tex]Being the vertex (h,k)So first complete the square[tex]y = x^{2} -5x -6 \\y = x^{2} - 2(2.5x) -6 \\y = x^{2} - 2(2.5x) +2.5^{2} - 2.5^{2} -6 \\y = (x^{2} -2(2.5x) + 2.5^{2}) -6.25 - 6 \\y = (x-2.5)^{2} -12.25[/tex]Vertex : (2.5,-12.25)b.To find the y-intercept you need to replace the equation when x = 0 and get y[tex]y = (0)^{2} - 5(0) -6\\y = - 6[/tex]c. To find the x-intercept you need to replace the equation when y = 0 and get x[tex]0 = x^{2} - 5x -6 \\0 = (x-6)(x+1)\\x = 6\\x = -1[/tex]