The endpoints of AB are A(2, 3) and B(8, 1). The perpendicular bisector of AB is CD, and point C lies on AB. The length of CD is (root of 10) units.The coordinates of point C are (-6, 2) (5, 2) (6, -2) (10, 4) . The slope of is -3 -1/3 1/3 3 . The possible coordinates of point D are (4, 5) (5, 5) (6, 5) (8, 3) and (2, 1) (4, -1) (5, -1) (6, -1) .Please pick 1 answer for all the questions
Accepted Solution
A:
Comment If C lies on AB Then it must be the midpoint of AB because CD is the Perpendicular Bisector of AB
Using y2 = 3x - 13 for x2 = 4 then y2 = 3(4) - 13 y2 = - 1
for x2 = 6 y2 = 3*6 - 13 y2 = 5
Possible Answers for D D = (4,-1) D = (6,5)
I've included a graph to show a graphical solution.
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